PREFACE| SPECIFICATION| MIDDENDORF| SUMMARY| CALCULATION| CONSTRUCTION| TRUSS & PARRAL| STAD A'DAM| CONCLUSION

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    Now it is known what length of wire has to fit on the drum of the winch. The proportional differences in length between port- and starboard side are also known. The next step is to design a drum on which both quantities will fit.
However, there are 3 shafts (with 3 pairs of drums), which are driven simultaneously. When the dimensions of the first set of drums is settled, the two remaining pairs are related to this one, because they have to brace around the yards in the same amount of revolutions.

       Because the existing winches are the starting point for this essay, it is tried to stay as close as possible to the existing dimensions. The measurements to follow are therefore taken from Bemastung und Takelung of F.L. Middendorf. What should we do without him!

The lower yard drum measures: length 75 cm, small diameter 27 cm, and large diameter 38 cm.
The lower topsail yard measures: length 65 cm, small diameter 22 cm, and large diameter 35 cm.
The upper topsail yard measures: length 65 cm, small diameter 20 cm, and large diameter 35 cm.
For the bars (ribs) on the drum we take 3 cm.
The diameters of the drums are measured on the outside of the bars, this out of practical point of view.


       The drawing represents a cross-section of a drum. The characters s and t represent the moveable discs, their diameter includes the bars. The characters p and q represent the smallest and the largest diameter of the ends of the drum. These are of interest, because with those values one works, when fine-tuning the winch.
Value x is the distance from the foreside of the drum to the heart line of disc s. Value y is the distance from the foreside of the drum to the heart line of disc t. The coning is given by b and at last, the length of the bars is presented by z.

For b counts:       tan b = (t - s) / 2 . (y - x)

       From this equation the conclusion can be extracted that if the discs s and t are moved in the same direction, over the same distance, only the total diameter of the drum will change. If, however, only one of the discs is moved, or both in different ways, the diameter as well as the coning will change.
Next the diameter p has to be determined to serve, together with value b, as input for the calculation of the total circumference of the drum etc. When the difference in radius of s and p is given by a, then the difference between their diameters is 2 * a.
In the same logic for q and p, the difference is 2 * k.

For p:        p = s - 2 . a
For a:        a = x . tan b    Þ     p = s - 2 . (x . tan b)
For q:        q = p + 2 . k
For k:        k = z . sin b    Þ     q = p + 2 . (z . sin b)

       With these equations it should be possible to determine the angle b for the coning and the smallest and largest diameter of the drum for every position of the discs s and t.



This drawing above shows the following magnitudes:

  • r is the radius of the smallest circumference
  • d is the diameter of the steel wire
  • b is the angle of the coning
  • v is the increasing radius of the drum with every next turn

The total circumference of the drum (O) must equal the length of the brace: L.
The circumference of a circle is 2pr. The radius of the drum increases after every revolution
with v.

For v counts:     v = d . tan b
For the circumference of the smallest radius counts:     r = r + d
The radius of the drum is increased with the diameter of the steel wire, because the circumference of the drum is measured on the outside of the wire, not on the empty bars.

For every next radius counts:
       r1 = r + d . tan b + d
       r2 = r1 + d. tan b + d
       rx = rx-1 + d . tan b + d

The total drum circumference, measured over the wire, is called O.
       O = 2pr + 2pr1 + 2pr2 + 2pr3 + 2pr4 + ....+ 2prx    Þ
       O = 2p(r + r1 + r2 + r3 + r4 +....+ rx)

One can say that O always has to be equal or greater then the brace length L. Otherwise it could happen that drum can not stow all the wire.
If x represents the number of windings on the drum, then 2prx is the circumference of the last and so the greatest winding on the drum. Of this last winding perhaps only a fraction is used, to know:
       O - L / 2prx

To work out exactly how many windings (x) the drum contains, one can state:
       x = x - 1 + O - L / 2prx

So far the theory!
If you are still reading this site at this point, you have shown some dogged persistence.

Continue.





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